x^2-5x+20=0

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Solution for x^2-5x+20=0 equation:


Simplifying
x2 + -5x + 20 = 0

Reorder the terms:
20 + -5x + x2 = 0

Solving
20 + -5x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + -5x + -20 + x2 = 0 + -20

Reorder the terms:
20 + -20 + -5x + x2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -5x + x2 = 0 + -20
-5x + x2 = 0 + -20

Combine like terms: 0 + -20 = -20
-5x + x2 = -20

The x term is -5x.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5x + 6.25 + x2 = -20 + 6.25

Reorder the terms:
6.25 + -5x + x2 = -20 + 6.25

Combine like terms: -20 + 6.25 = -13.75
6.25 + -5x + x2 = -13.75

Factor a perfect square on the left side:
(x + -2.5)(x + -2.5) = -13.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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